Question

A man is known to speak truth 3 out of 4 times. He throws a die and a number other than 6 comes up. Find the probability that he reports it is a 6.​

Answer 1

Answer:

P(man speaks truth)=3/4

P(man speaks false)=1-3/4

                                 =4-3/4

                                 =1/4

P(no. other than 6 comes up and he tells it is 6)

⇒P(man speaks false)=1/4

Your answer:

1/4

Answer 2

Answer:

He throws a die arid report that it is six. The probability that it actually a six is. = Hence, the required probability = ⅜.

Step-by-step explanation:

Hope it's correct thank you please mark me as a brain lies ฅ'ω'ฅ