A man is known to speak truth 3 out of 4 times. he throws die and reports that it is a 6. the probability that it is actually a 6 is
a. 3/7
b. 4/11
c. 3/8
d. 2/7
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Answer:
Step-by-step explanation:
Let assume the following events
E₁ : die show a number 6.
E₂ : die do not show a number 6
E : a man reports that 6 occurs on the die.
Now,
Now,
and
Now, By definition of Bayes Theorem, we have
So, on substituting the values, we get
Hence,
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