Question

A man is moving eastward with velocity of 4 kmph, finds wind appears to blow directly from the north

Answer 1

Ans➡️

Using +x = east and +y = north

Suppose velocity of wind is (X, Y)

Velocity of person, V = (3, 0)

Velocity of wind relative to person = (X,Y) - (3, 0) = (X – 3, Y)

Since wind appears to blow directly from the north, the east-west component (X – 3) must be zero:

X -3 = 0

X = 3km/hr

Velocity of person, V = (6, 0)

Velocity of wind relative to person = (X,Y) - (6, 0) = (X-6, Y) = (3- 6, Y) = (- 3, Y)

Since relative velocity is from the north east (direction south west), this is an angle of tan-1(1) = 45degrees.(south of west).

The x and y components of the relative velocity must be equal, beecause tan(45)=1, so Y = -3km/hr

Wind vector = (X, Y) = (3, -3) km/hr

Wind velocity = sqrt(3^2 + 3^2) = 4.2km/hr

Direction to the south east (from the north west)

Hope this helps you ☺️☺️✌️✌️❤️❤️