Math, asked by devishome46871, 1 year ago

A man is riding a bike with front and back wheel circumference of 40 inches and 70 inches respectively. if the man rides the bike on a straight road without slippage, how many inches will the man have travelled when the front wheel has made 15 revolutions more than the back wheel?

Answers

Answered by abhi178
13
circumference of front wheel = 40 inches
circumference of back wheel = 70 inches
now the man rides the bikes on a straight road without slippage.
Let number of revolutions made by front wheel is n
then number of revolutions made by back wheel = n - 15

in case of distance travelled by bike ,
distance covered by back wheel = distance covered by front wheel
so, 70(n - 15) = 40n
=> 70n - 1050 = 40n
=> 30n = 1050
=> n = 35

now, distance travelled = 40n = 70(n - 15)
= 1400 inches .
Answered by gogiya167
2

See the attachment.

Distance covered by both wheel eill be same.

Hence we will use relationship between distance,circumference and number of revolutions.


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