A man is riding a bike with front and back wheel circumference of 40 inches and 70 inches respectively. if the man rides the bike on a straight road without slippage, how many inches will the man have travelled when the front wheel has made 15 revolutions more than the back wheel?
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Answered by
13
circumference of front wheel = 40 inches
circumference of back wheel = 70 inches
now the man rides the bikes on a straight road without slippage.
Let number of revolutions made by front wheel is n
then number of revolutions made by back wheel = n - 15
in case of distance travelled by bike ,
distance covered by back wheel = distance covered by front wheel
so, 70(n - 15) = 40n
=> 70n - 1050 = 40n
=> 30n = 1050
=> n = 35
now, distance travelled = 40n = 70(n - 15)
= 1400 inches .
circumference of back wheel = 70 inches
now the man rides the bikes on a straight road without slippage.
Let number of revolutions made by front wheel is n
then number of revolutions made by back wheel = n - 15
in case of distance travelled by bike ,
distance covered by back wheel = distance covered by front wheel
so, 70(n - 15) = 40n
=> 70n - 1050 = 40n
=> 30n = 1050
=> n = 35
now, distance travelled = 40n = 70(n - 15)
= 1400 inches .
Answered by
2
See the attachment.
Distance covered by both wheel eill be same.
Hence we will use relationship between distance,circumference and number of revolutions.
Attachments:
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