Question

A man is running at 10km/he in a parallel track in the same direction of a train which is moving at 55 km/hr. He is 260 Meters ahead of the train if the lenth of train is 140 meters in what time the train will cross the man?

Answer 1

Answer:

$\huge\underline\mathfrak\red{❥Answer}$

Step-by-step explanation:

$time = \frac{distance \: coverd}{speed} \\ distance \: to \: be \: coverd \: = 260 + 140 = 400m \\ relative \: speed \: = 55 - 10 = 45k m \: per \: hour \\ relative \: speed \: in \: ms \: = 45 \times \frac{5}{18} = \frac{75}{6} \\ time = 400 \times \frac{6}{75} = 32sec$

Answer 2

Answer:

The train will cross the man in 32 sec

Step-by-step explanation:

Given that,

A man is running at 10km/hr in a parallel track in the same direction of a train which is moving at 55 km/hr. He is 260m ahead of the train.We are required to find the time in which the train will cross the man.

We know that,length of the train=140m

Distance between the man and the train=260m.

Hence,the total distance to be covered by train to cross the man is

$140+260=400m$

Now,the speed of the man is $V_{m}=10km/h$

The speed of the train is $V_{t}=55km/h$

As the train and man are moving parallel to each other,the relative speed of train with respect to the man is

$V_{tm}=V_{t}-V_{m}=55-10=45km/h=45\times\frac{5}{18} =12.5m/s$

Now the time taken by train to cross the man is the ratio of distance to be covered and relative speed.Hence,

$t=\frac{400}{12.5} =32sec$

Therefore,The train will cross the man in 32 sec

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