Question

a man is running on horizontal road has half the kinetic energy of aboy of half of his mass. when man speed up by 1m/s ,then his kinetic energy becomes equal to kinetic energy of the boy the original speed of the man is ​

Answer 1

Answer:

Explanation:

1/2MV^2=1/4 x MV1^2

4M =  maSS of man

V^2= V1^2/4

V= V1/4

where V= Velocity of mass

V1 = Velocity of  boy

1/2M(V+1)^2=1/2(  M/2)V1^2

(V+1)^2=(V1)^2/2

(V+1)^2=(√2V)^2

V+1 = ±√2V

V = √2+1

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