Question

A man is running on horizontal road has half the
kinetic energy of a boy of half of his mass. When man
speeds up by 1 m/s, then his KE becomes equal to
KE of the boy, the original speed of the man is
(1) 2 m/s (2) (V2 - 1) m/s
(3) 2 m/s
(4) (V2+1) m/s​

Answer 1

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