Question

a man is running towards east with a velocity with 6m/s inturn towards north in a time interval of 2s but has same velocity then find the velocity both in magnitude and direstion

Answer 1

Answer:

Explanation:

Let the east direction to be  

i

^

 and north direction be  

j

^

​  

.

Thus displacement of the man    

S

=8  

i ^  +6  j

^

​  

 

So, magnitude of displacement  ∣  

S

∣=  6  2 +8  

2  =  100

​  

=10M

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