A man is running with velocity 5 km/h towards east and rain is falling vertically down with speed 5 km/h. Direction of rain w.rt. man is (1) 30° with vertical (2) 60° with vertical (3) 45° with vertical (4) 90° with vertical
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Answered by
0
Answer:
Explanation:
V
Rain,Person
=V
Rain
−V
Person
=−5
j
^
(vertically down)
Thus, V
Rain
−(−5
i
^
)=−5
j
^
(west means −5
i
^
)
or, V
Rain
=−5
i
^
−5
j
^
Thus, magnitude = 5
2
km/hr, direction is in 3rd quadrant, i.e. clockwise to vertical at an angle of tan
−1
(
5
5
)=45
o
to vertical
Answered by
0
Answer:
V
Rain,Person
=V
Rain
−V
Person
=−12
j
^
(vertically down)
Thus, V
Rain
−(5
i
^
)=−12
j
^
or, V
Rain
=5
i
^
−12
j
^
Thus, direction is tan
−1
(
12
5
)=22
o
37
′
east of vertical (+5,−12) means 4
th
quadrant, thus east of vertical.
Explanation:
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