Question

a man is s=9 m behind the door of a train when it starts moving with acceleration a=2...

Answer 1

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Answer 2

Answer:

Explanation:

S=9

a=2m^-2

9=1/2*2t^2

t=3

Therefore: v=u+at

v=0+2*3

v=6ms^-1

Distance of the man (to the train)

D=S*P

D=6*3

D=18m.