A man is sitting on the top of a cliff starts dropping balls. After each second drops one ball. What is the distance travelled by the 3rd, 4th and 5th ball when the 6th ball is being dropped?
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X=1/2gt2 (u=0 bcoz ball is drop &a=g free falling)
3rdball=1/2g3^2=45m
4thball=1/2g2^2=20m
5thball=1/2g1^2=5m
6thball drop after 5sec of first ball drop so according this time 3,4,5ball acc to 6thball count 3rdball drop 3 sec before the 6th ball &4th ball drop 2 sec before 6th ball &5th ball drop 1sec before the 6 that ball
3rdball=1/2g3^2=45m
4thball=1/2g2^2=20m
5thball=1/2g1^2=5m
6thball drop after 5sec of first ball drop so according this time 3,4,5ball acc to 6thball count 3rdball drop 3 sec before the 6th ball &4th ball drop 2 sec before 6th ball &5th ball drop 1sec before the 6 that ball
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