Question

A man is six times as old as his son. Twenty years later, the man will be twice as old as his son. Find the age of the man when his son was born.

Answer 1

Let the present age of son be x years

Present age of man = 6x years

20 years later

Age of son = x + 20

Age of man = 6x + 20

According to the question

6x + 20 = 2 ( x + 20 )

6x + 20 = 2x + 40

6x – 2x = 40 – 20

4x = 20

x = 20/4

x = 5

Present age of son = 5years

Present age of man = 30 years

Age of man when his son was born

= 30 – 5 = 25 years

Answer 2

Answer:

The man is currently 30 years old and his son is 5 yrs old. Father is 6 times as old.

20 years in the future the father is 50 yrs old and the son is 25 yrs old. Father would be then, 2 times the son’s age.

6x + x = 2x + x +20

7x = 3x +20. subtract from each side the unknown own variable x

4x=20. X=5

Son 5 now and 25 future

Dad 30 now and 50 future

Prove it:

6(5) + (5) = 2(5) + (5)+20

30+5=10+5+20 ; 35=35.

PAST AND FUTURE ALIGN

30 YRS MINUS SONS AGE OF 5 YRS = 25 YEARS

THE DAD WAS 25 WHEN JUNIOR WAS BORN

hope it helps u

please mark my answer as a brainliest..

$: )$