Question

A man is six times as old as his son. Twenty years
later, the man will be twice as old as his son
Find the age of the man when his son was born

Please use algebraic method also give relevant answers and I will mark u brain liest ​

Answer 1

Answer:

Step-by-step explanation: Let the age of the son is x , then the age of the man is 6 x. After 20 years

the age of the man will be 6 x + 20 and the age of the son will be x + 20. Then

6x+20=2(x+20)

⟹6x+20=2x+40⟹6x−2x=40−20⟹4x=20

⟹x=5

Hence the son is 5 years old and the father is 30 years old. Therefore

the father was 25 years old when his son was born.

Answer 2

Step-by-step explanation:

Thus the man when his son was born is 30 (6x=6*5) years old. A father's age is 5 times the age of his 6 sons. After 7 years, his age will be twice the sum of the ages of his sons.