Question

a man is six times as old as his son. twenty years later, the man will be twice as old as his son. find the age of the man when his son was born

Answer 1

Answer:

Age of man= 30

Age of boy= 5

Step-by-step explanation:

Let age of man=x

Let age of boy=y

Now,

Given: man is six times as old as his son

==>x=6y-----------1.

After 20 years,

Age of man= x+20

Age of boy= y+20

Given: man will be twice as old as his son

==> x+20=2(y+20)

==>x+20=2y + 40

==>x- 2y =20------------2.

Applying 2 in 1

==>6y-2y=20

==>4y=20

==>y=5

x=6y

 =6*5

 =30

Answer 2

The age of the man when his son was born was 25 years

Step-by-step explanation:

Let the age of son be x

We are given that a man is six times as old as his son.

So, Age of man = 6x

Age of man after 20 years = 6x+20

Age of son after 20 years = x+20

We are given that twenty years later, the man will be twice as old as his son

So, 6x+20=2(x+20)

6x+20=2x+40

4x=20

x=5

So, The age of son is 5 years

Age of Man = 6x=6(5)=30 years

Age of the man when his son was born = Age of Man 5 years ago = 30-5 = 25 years

Hence The age of the man when his son was born was 25 years

#Learn more:

The ratio of the present ages of a man and his son is 9:4.when the man was 36 years old his daughter was born,.if the son is 11 years elder to the daughter. find the present age of the man?​

https://brainly.in/question/9910370