A man is standing 40m behind the bus. Bus starts with constant acceleration 1m/s square and also at the same instant the man also starts moving with constant speed 9m/s . Find the time taken by the man to catch the bus?
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1
Answer:
initial velocity =0
D=9×t
t^2upon t=9×t
t^2 upon 2×t
t upon 2=9
t=9×2
t=18 sec
Answered by
0
Answer:
Time taken by man to catch the bus is 18 seconds
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