a man is standing at the top of 105 m high tower he throws a ball vertically upwards with a velocity of 20m/s after how many seconds will ball pass him going downward how long after its release will the ball reaches the ground
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y=y1 + uy + 1/2 at t^2
h=0 + 0 * T+1/2gt^2
t= under root 2*h /g
under root 2*105 / 9.8
=4.629 sec .
h=0 + 0 * T+1/2gt^2
t= under root 2*h /g
under root 2*105 / 9.8
=4.629 sec .
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