a man is standing at the top of a 100 m high tower he throws a ball vertically upwards with a velocity of 20m/s after what time wil the ball pass him going downwards how long after its release will the ball reach the ground
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T = 2u/g
= 2 * 20 / 10
= 4 seconds
After 4s ball will pass him.
v = sqrt(2gH)
v = sqrt(2 * 10 * 100)
v = 10 * sqrt(20)
v = 44.72 m/s
v = u + at
t = (v - u) / a
t = (44.72 - 20) / 10
t = 2.472 seconds
Total time for ball to reach the ground = 4 + 2.472 = 6.482 seconds
= 2 * 20 / 10
= 4 seconds
After 4s ball will pass him.
v = sqrt(2gH)
v = sqrt(2 * 10 * 100)
v = 10 * sqrt(20)
v = 44.72 m/s
v = u + at
t = (v - u) / a
t = (44.72 - 20) / 10
t = 2.472 seconds
Total time for ball to reach the ground = 4 + 2.472 = 6.482 seconds
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