a man is standing between two lamp posts on a horizontal line dividing the distance between them in the ratio 1:2 the height of man is 2m. it is noticed than shadow of the man with respect to first lamp post just touches the foot of second lamp post if the distance between the post is 30m. find the height of the first post
Answers
Given:
The height of the man = 2 m
A man is standing between two lamp posts on a horizontal line dividing the distance between them in the ratio 1:2
The distance between the two lamp post is 30 m
The shadow of the man with respect to the first lamp post just touches the foot of the second lamp post
To find:
The height of the first post
Solution:
Referring to the figure attached below, we have
AB = height of the lamp post 1
BE = 30 m = distance between the two lamp post
CD = 2 m = height of the man
Since the divides, the horizontal line dividing the distance between the lamp post 1 and 2 in the ratio of 1:2 and also BE = 30 m
So, let's assume BD = x and DE = 2 x
∴ BD + DE = BE
⇒ x + 2x = 30
⇒ 3x = 30
⇒ x =
⇒ x = 10 m
∴ DE = 2x = 2 × 10 = 20 m
Now, consider ΔABE and ΔCDE, we have
∠E = ∠E ....... [common angle]
∠ABE = CDE = 90° ..... [both lamp and man stands vertical on the horizontal line]
∴ ΔABE ~ ΔCDE ...... [by AA similarity]
We know that the corresponding sides of two similar triangles are proportional to each other.
∴
substituting CD = 2, BE = 30 & DE = 20
Thus, the height of the first lamp post is 3 m.
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Step-by-step explanation:
answer for this question is 3 m