Question

A man is standing on a cart of mass double the mass of the man. Initially the cart is at rest. Now the man jumps horizontally with a velocity u relative to the cart. Then calculate the work done by the man during the process of jumping.

Answer 1

Explanation:

2mv=m(u−v)

∴v=

3

u

∴u−v=

3

2u

KE=

2

1

×m(

3

2u

)

2

+

2

1

(2m)(

3

u

)

2

=

3

1

mu

2

Using Work Energy Theorem

Work Done = Change in kinetic Energy

W=

3

1

mu

2

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