Question

a man is standing on a tower and he throws a ball vertically upward with a velocity of 14m/s.The ball reaches ground 4.6sec later . What is the maximum height reached by the ball. how hogh is the building,with what velocity will it strike to the ground

Answer 1

hey
u=14
v=0
a=-10
t= ?

a=(v-u)/t
-10 = (0-14)/t
t=1.4 sec

it means it requires 1.4 second to reach upwards

now 4.6 -1.4= 3.2 sec required to reach at bottom

here
u=0
v=?
t=3.2 sec
a=10
s=?

so now by
a=(v-u)/t
you will find v

and

s=ut +(at^2)/2

you will find s ,


also find s in upper part according to data given in first part..

and subtract both s ..you will find height of building