Question

A man is standing on a weighing machine placed in a lift. When lift is stationary his wieght is recorded as 40 kg. If the lift is accelerated upwards with an acceleration of 2 mis" then find the weight recorded in the machine (g=10m/s)​

Answer 1

Answer:

48N

Explanation:

F = mg

mg = 40

m = 40/10 = 4(when lift is stationary)

Now,

when lift accelerate upward

F = m(g+a)

F= 4(10+2)

F= 48N

Answer 2

Answer:

48 kg

Explanation:

We are given that weight of lift=40 Kg

Acceleration =$2m/s^2$

We know that weight=mg

We are given that g=$10m/s^2$

We have to find the weight recorded in the machine

Weight of lift=40 kg

When lift is accelerated upwards with acceleration

Then force =$m(g+a)=40(10+2)=480 N$

Weight =$\frac{480}{10}=48 Kg$

Hence, the weight recorded in the machine=48 kg