A man is standing on an international space station, which is orbiting earth at an altitude 520 km with a constant speed 7.6 km/s, if the man's weight is 50 kg, his acceleration is
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Answer:
8.6 m/s square
Explanation:
v= 7600 m/s
r= 6400+510 km
=6920 km= 6920 * 1000m
a= /r
=/6920*1000
= 76 square/692/76*76/692
= 8.6 m/s square
Step-by-step explanation:
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