Question

a man is standing on the roof of house height h throws one particle vertically upwards and another particle horizontally with the same velocity u.the ratio of their velocities when they reach the earth's surface will be?​go

Answer 1

Answer:

1:1

Explanation:

In both the cases the same gravitational potential energy at the roof top is converted to kinetic energy at the base of house

for first case applying law of conservation of energy

mgh=1/2 mv1^2

and for 2nd case

mhg= 1/2 mv2^2

equating both we get v1=v2