Question

A man is standing on top of a building 100 m high. He throws two balls vertically upwards, one
at t = 0 and other after a time interval (less than 2 s). The later ball is thrown at a velocity of half
the first. The vertical gap between first and second ball is 15 m at t = 2 s. The gap is found to remain
constant. The velocities with which the balls were thrown are (Take g = 10 m s-2)


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Answer 1

20 m s-1, 10 m s-1

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