Physics, asked by abhi112569, 1 year ago

A man is swimming in a lake in a direction of 30° East of North with a speed of 5 km/h and a cyclist is
going on a road along the lake shore towards East at a speed of 10 km/h. In what direction and with
what speed would the man appear to swim to the cyclist.​

Answers

Answered by Anonymous
57

Answer :

5√3 km/hr 60° west of north.

Step-by-step explanation :

Swimmer speed 5 km/h  30° East Of North.

Swimmer  speed towards North = 5 Cos30° = 5√3/2  km/hr.

Swimmer speed towards East = 5 Sin30° = 5/2  km/hr.

Cyclist Speed = 10 km/h  East  ( north = 0).

The man appear to swim to the cyclist =  Speed of Swimmer - Speed of cyclist

= 5√3/2  km/hr North  &  ( 5/2  - 10)  km/Hr East.

=   5√3/2  km/hr North & 15/2 km hr West   ( -East = West).

Resultant speed = √(5√3/2)² + (15/2)²  = 5√3  km /hr.

Angle = Tanα = (15/2)/(5√3/2) = √3

=> α = 60°.

60° West of North.

The man appear to swim to the cycist 5√3  km /Hr 60° West of North.

Hence, it is solved.

Answered by Anonymous
46

hey there

refer to attachment

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