A man is swimming in a lake in a direction of 30° East of North with a speed of 5 km/h and a cyclist is
going on a road along the lake shore towards East at a speed of 10 km/h. In what direction and with
what speed would the man appear to swim to the cyclist.
Answers
Answered by
57
Answer :
→ 5√3 km/hr 60° west of north.
Step-by-step explanation :
Swimmer speed 5 km/h 30° East Of North.
Swimmer speed towards North = 5 Cos30° = 5√3/2 km/hr.
Swimmer speed towards East = 5 Sin30° = 5/2 km/hr.
Cyclist Speed = 10 km/h East ( north = 0).
The man appear to swim to the cyclist = Speed of Swimmer - Speed of cyclist
= 5√3/2 km/hr North & ( 5/2 - 10) km/Hr East.
= 5√3/2 km/hr North & 15/2 km hr West ( -East = West).
Resultant speed = √(5√3/2)² + (15/2)² = 5√3 km /hr.
Angle = Tanα = (15/2)/(5√3/2) = √3
=> α = 60°.
60° West of North.
The man appear to swim to the cycist 5√3 km /Hr 60° West of North.
Hence, it is solved.
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hey there
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