Question

A man is three times as old as his son. After 12 years he will be twice as old as his son at that time find their present ages

Answer 1

Let son's present age be x.

Father's present age = 3x.

After 12 years,

Son's age = x + 12

Father's age = 3x + 12

Now,

After 12 yrs father will twice as old as son. So,

3x + 12 = 2(x +12)

3x + 12 = 2x + 24

3x - 2x = 24 - 12

x = 12

Sons present age = 12 years

Fathers present age = 3x = 3 ☓ 12 = 36 years

Answer 2

son ages is 12 yrs and father age is 36 yrs......