A man is three times as old as his son. After 12 years he will be twice as old as his son at that time find their present ages
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Answered by
2
Present year,
Age of son = x
Age of man = 3x
After 12 years,
Age of son = x + 12
Age of man = 3x + 12
According to the question,
3x + 12 = 2(x + 12 )
3x + 12 = 2x + 24
3x - 2x = 24 - 12
x = 12
So,
The present age of son = 12 years.
The present age of man = 36 years.
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Age of son = x
Age of man = 3x
After 12 years,
Age of son = x + 12
Age of man = 3x + 12
According to the question,
3x + 12 = 2(x + 12 )
3x + 12 = 2x + 24
3x - 2x = 24 - 12
x = 12
So,
The present age of son = 12 years.
The present age of man = 36 years.
Hope it may help you !!!!!
Pls mark as brainlest !!!!
abhineet75:
thanks body
Answered by
0
Answer:
(12,36)
Step-by-step explanation:
let son = x
father = 3x
then after 12 years,
Age of son = x + 12
Age of man = 3x + 12
which impiles;-
3x + 12 = 2(x + 12 )
3x + 12 = 2x + 24
3x - 2x = 24 - 12
x = 12
So,
The present son's age= 12 years.
The present father's age = 36 years.
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