Math, asked by abhineet75, 11 months ago

A man is three times as old as his son. After 12 years he will be twice as old as his son at that time find their present ages

Answers

Answered by Ayushasutkar1
2
Present year,
Age of son = x
Age of man = 3x
After 12 years,
Age of son = x + 12
Age of man = 3x + 12
According to the question,
3x + 12 = 2(x + 12 )
3x + 12 = 2x + 24
3x - 2x = 24 - 12
x = 12
So,
The present age of son = 12 years.
The present age of man = 36 years.
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abhineet75: thanks body
Answered by lovendsken
0

Answer:

(12,36)

Step-by-step explanation:

let son = x

father  = 3x

then after 12 years,

Age of son = x + 12

Age of man = 3x + 12

which impiles;-

3x + 12 = 2(x + 12 )

3x + 12 = 2x + 24

3x - 2x = 24 - 12

x = 12

So,

The present son's age= 12 years.

The present father's age = 36 years.


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