Question

A man is three times as old as his son. Eight years ago the man was 7 times as old as his son. Find their present ages.

Answer 1

9th class problem?
y =3x
y-8=3x-8(8years ago)
y-8=

Answer 2

let son's present age be x
then
man's present age will be 3x
7(x-8) = (3x-8)
7x-56=3x-8
4x=48
x=12
then son's present age=12
and man's present age=12*3=36