A man is three times as old as his son. Eight years ago the man was 7 times as old as his son. Find their present ages.
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9th class problem?
y =3x
y-8=3x-8(8years ago)
y-8=
y =3x
y-8=3x-8(8years ago)
y-8=
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let son's present age be x
then
man's present age will be 3x
7(x-8) = (3x-8)
7x-56=3x-8
4x=48
x=12
then son's present age=12
and man's present age=12*3=36
then
man's present age will be 3x
7(x-8) = (3x-8)
7x-56=3x-8
4x=48
x=12
then son's present age=12
and man's present age=12*3=36
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