Question

A man is three times as older as his son after 15 years he will be only twice as his son.find their presents age​

Answer 1

$\mathfrak{\large{\underline{\underline{Answer: }}}}$

Son is presently 15 years old and Man is 45 years old.

$\mathfrak{\large{\underline{\underline{Step-by-step\:explanation:}}}}$

Given :

A man is = 3 times old as his son

After 15 years = man will be twice old as his son

To find :

Their present ages

Solution :

Let the present ages be -

• Son as x
• Man as 3x

After 15 years -

• Son = (x + 15)
• Man = (3x + 15)

According to the Question -

$\bigstar{\green{\boxed{\green{\boxed{\red{\sf{(3x+15)=2(x+15)}}}}}}}$

$\sf{\longrightarrow} \: (3x+15)=2(x+15) \\ \sf{\longrightarrow} \:3x + 15 = 2x + 30 \\ \sf{\longrightarrow} \:3x - 2x = 30 - 15 \\ \sf{\longrightarrow} \:x = 15$

Son is = 15 years old

$\rule{300}{1.5}$

★ Value of 3x

$\sf{\longrightarrow} \:3(15) \\ \sf{\longrightarrow} \:45$

Man = 45 years old.

$\therefore$ Son is presently 15 years old and Man is 45 years old.

Answer 2

$\sf{Hello,Brainly\:User}$

According to the given question

A man is three times as older as his son after 15 years he will be only twice as his son and here we need to find their presents age.

Let y be the age of son.

Let 3y be the age of man.

15 years after the ages of man and the son.

(x + 15) is the age of son.

(3x + 15) is the age of man.

Using Identity

$\bf⟹(3y + 15) = 2(y + 15)$

Hence,

$\sf⟹(3y+ 15) = 2(y + 15) \\ \sf⟹(3y + 15 = 2y + 30) \\ \sf⟹(3y - 2y) = (30 - 15) \\ \sf⟹(y = 15)$

Therefore, 15 years age of son.

Adding values for (3x)

$</strong><strong>\</strong><strong>s</strong><strong>f</strong><strong>⟹3..(15) = 45$

Therefore, 15 is age of son and 45 is the age of man. _[Their Present ages]