Math, asked by neerajomer, 1 year ago

a man is three times older than his son. The difference between their ages is 32 years, find their present ages.

Answers

Answered by dhanashree04
7
consider son's age as x years
then the age of the man will be 3x
according to given conditions 3x-x=32
2x=32
x=16
son's age = x = 16 years
man's age = 3x = 48 years
Answered by BlackVenom05
4

Solution -

Let the age of son be x yrs

So, the age of man be 3x yrs

According to Question,

Difference of their ages = 32

3x - x = 32

⇒ 2x = 32

⇒ x = 32/2

⇒ x = 16

Required Ages -

Son's age = x = 16 yrs

Man' age = 3x = 3(16) = 48 yrs

∴ The present age of Man is 48 years and the present age of Son is 16 years

#Be Brainly

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