Question

a man is thrice as old as his son . 12 years ago man was two times as old as his son .Find their present age

Answer 1

$\huge\red{HELLO\:MATE}$

Let the present age of the site be x.
Then the age of his father = 3x.
Age if the son 12 yrs. ago = x- 12.
Age if the father 12 yrs. ago =3x -12.

ATQ , 2 (x-12)=3x-12.
or. 2x -24=3x-12.
or. 2x-3x=-12+24.
or. -x. =-12
Therefore x =12.

present age of son =x =12yrs.
present age of the man =3x =3×12=36yrs.

Answer 2

Answer: Let x and y be the present ages of the man and his son respectively.

Man is thrice his age of his son.

x=3y          ....(1)

Therefore,

12 years ago,

Age of the man=x-12

Age of his son=y-12

The man is twice the  age of his son.

x-12=2(y-12)

x-12=2y-24

3y-12=2y-24     [BY 1]

3y=2y-24+12

3y=2y-12

3y-2y=-12

y=-12

therefore x=3y

x=3(-12)

X=-36.

Since the ages cannot be negative, the given statement is wrong!!.

Step-by-step explanation: