a man is thrice as old as his son. 5 years ago the man was four times as old as his son .find there present age
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Let the present ages of the man and his son be "x " and "y" respectively.
As per the question,
x=3y -------> (1)
Ages five years ago,
age of father = x−5
age of son =y−5
So,
x−5=4(y−5)
x−5=4y−20
from equation (1)
3y−5=4y−20
4y−3y=−5+20
y=15
x=3y
x=3∗15=45
Hence, present ages of father and son are :-
age of father = x=45years
age of son = y=15years
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