A man is thrice as old as his son five year ago the man was four times as old as his son find their parent ages
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let the age of Man be X
let the age of son be y
ATQ
x = 3y -----(i)
x-5 = 4( y-5 )
x-5 =4y-20
x-4y= -20+5
x-4y=-15
3y-4y=-15
-y=-15
y=15
So son age is 15 years
x=3y
x=3×15
x=45
So father age is 45 years
let the age of son be y
ATQ
x = 3y -----(i)
x-5 = 4( y-5 )
x-5 =4y-20
x-4y= -20+5
x-4y=-15
3y-4y=-15
-y=-15
y=15
So son age is 15 years
x=3y
x=3×15
x=45
So father age is 45 years
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