Math, asked by rajkumar8384236, 1 year ago

A man is thrice as old as his son. five years ago the man was four times as old as his son. find their present ages.​

Answers

Answered by ihrishi
19

Step-by-step explanation:

Let the present age of son = x years

Therefore,

Present age of father = 3x years

5 years ago:

Son's age = x - 5

Father's age = 3x - 5

According to the given information:

3x-5= 4(x - 5)

3x - 5 = 4x - 20

20 - 5 = 4x - 3x

15 = x

Therefore, 3x = 3 * 15 = 45

Thus,

Son's present age = 15 years

Father's present age = 45 years

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