Question

A man is thrice as old as his son. five years ago the man was four times as old as his son. find their present ages.​

Answer 1

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Answer 2

Step-by-step explanation:

Let the present ages of the man and his son be "x " and "y" respectively.

                             -------> (1) 

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 So,

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 So,x−5=4(y−5)

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 So,x−5=4(y−5)x−5=4y−20

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 So,x−5=4(y−5)x−5=4y−20from equation (1) 

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 So,x−5=4(y−5)x−5=4y−20from equation (1) 3y−5=4y−20

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 So,x−5=4(y−5)x−5=4y−20from equation (1) 3y−5=4y−204y−3y=−5+20

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 So,x−5=4(y−5)x−5=4y−20from equation (1) 3y−5=4y−204y−3y=−5+20y=15

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 So,x−5=4(y−5)x−5=4y−20from equation (1) 3y−5=4y−204y−3y=−5+20y=15x=3y

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 So,x−5=4(y−5)x−5=4y−20from equation (1) 3y−5=4y−204y−3y=−5+20y=15x=3yx=3∗15=45

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 So,x−5=4(y−5)x−5=4y−20from equation (1) 3y−5=4y−204y−3y=−5+20y=15x=3yx=3∗15=45Hence, present ages of father and son are :-

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 So,x−5=4(y−5)x−5=4y−20from equation (1) 3y−5=4y−204y−3y=−5+20y=15x=3yx=3∗15=45Hence, present ages of father and son are :-age of father = x=45years

Let the present ages of the man and his son be "x " and "y" respectively.As per the question,x=3y                               -------> (1) Ages five years ago,age of father = x−5age of son =y−5 So,x−5=4(y−5)x−5=4y−20from equation (1) 3y−5=4y−204y−3y=−5+20y=15x=3yx=3∗15=45Hence, present ages of father and son are :-age of father = x=45yearsage of son = y=15years