Math, asked by rajendraaryanr2368, 11 months ago

A man is thrice as old as his son. Five years ago the man was 4 times as old as his son. Find their present ages.

Answers

Answered by yuvin3
3
son's age = x
father = 3x
five years ago
son x-5
father 3x - 5
4( x-5) = 3x-5
4x - 20 = 3x - 5
4x - 3x = - 5 + 20
x = 15
son's age = 15
father's age = 3×15= 45
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