A man is thrice as old as his son. Six years ago the man was four times as old as his
son. Their present age difference is
Answers
Answered by
0
Answer:
the difference of age 6×4 = 24
so the answer is 24 years
Answered by
2
Answer:
6 years ago..
let son's age be x
then man's age is y and its 4 times
y=4x----1
after 6 years, man's age is 3 times
y+6=3(x+6)
in this equation I put y's value as 4x from 1st equation
4x+6=3x+18
4x-3x=18-6
(x=12)
after 6 years
son'age=18 years
father's age=54 years
you can put in equation and check
Thanks
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