Question

A man is thrice as old as his son . Three years ago the man was four times as old as his son . Find their present ages???​

Answer 1

Answer:

man=27

son=9

Step-by-step explanation:

Given,

A man is thrice as old as his son .

let man be 'm' son be 's'

m=3s

m/s=3/1

let m/s=3x/1x

Three years ago the man was four times as old as his son .

man three years ago

m=3x-3

s=1x-3

3x-3=4(x-3)

x=9

man age is 3x

3*27

son age is x=9

Answer 2

Step-by-step explanation:

Let the age of son be x

Let his father's age be 3x

Five years ago, age of son = x - 5

Five years ago, age of father = 3x - 5

5 years ago the man was four times as old as his son = 4(x - 5)

According to the question,

3x - 5 = 4(x - 5)

3x - 5 = 4x - 20

3x - 4x = -20 + 5

\cancel{-}

−

x = \cancel{-}

−

15

x = 15

Present age of son is x

=> 15 years

Present age of father =. 3x

=> 3 * 15

=> 45 years

∴ The age of son and his father is 15 years and 45 years respectively.