A man is thrice as old as his son . Three years ago the man was four times as old as his son . Find their present ages???
Answers
Answered by
1
Answer:
man=27
son=9
Step-by-step explanation:
Given,
A man is thrice as old as his son .
let man be 'm' son be 's'
m=3s
m/s=3/1
let m/s=3x/1x
Three years ago the man was four times as old as his son .
man three years ago
m=3x-3
s=1x-3
3x-3=4(x-3)
x=9
man age is 3x
3*27
son age is x=9
Answered by
2
Step-by-step explanation:
Let the age of son be x
Let his father's age be 3x
Five years ago, age of son = x - 5
Five years ago, age of father = 3x - 5
5 years ago the man was four times as old as his son = 4(x - 5)
According to the question,
3x - 5 = 4(x - 5)
3x - 5 = 4x - 20
3x - 4x = -20 + 5
\cancel{-}
−
x = \cancel{-}
−
15
x = 15
Present age of son is x
=> 15 years
Present age of father =. 3x
=> 3 * 15
=> 45 years
∴ The age of son and his father is 15 years and 45 years respectively.
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