Question

A man is throwing balls in air. He
throws next ball when previous one is
at highest point. If he throws each ball
after 2 seconds, then height to which
ball rises is (take g = 10 m/s2)
(a) 10 m
(b) 15 m
(c) 20 m
(d) 30 m​

Answer 1

Answer:

Explanation:

he is throwing 1/2 ball per second

2 sec = time of ascent

v=u+at

u=20 m/s

v^2-u^2=2as

400 = 20s

s=20 m