Question

A man is throwing balls in air. He throws next ball when previous one is at highest point. If he throws each ball after 2 seconds, then height to which ball rises is (take g = 10 m divided by s squared)

Answer 1

Explanation:

Throwing one when other is at the highest point. How high the balls rise if he throws twice a second. ∴S=12×9.8×12×(12)∘=9.88m1.225m.

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