A man is travelling on a flat car which is moving up a plane inclined at
cos thetha = 4/5 to the horizontal with a speed 5 m/s. He throws a ball towards a
stationary hoop located perpendicular to the incline in such a way that the
ball moves parallel to the slope of the incline while going through the centre
of the hoop. The centre of the hoop is 4 m high from the man's hand
calculate the time taken by the ball to reach the hoop in second.
Answers
Answer:
The time taken by the ball to reach the hoop is one second.
Explanation:
Given data :
A man is travelling on a flat car which is moving up a plane inclined.
It is given that:
cos thetha = 4/5
speed =5 m/s.
He throws a ball towards a
stationary hoop located perpendicular to the incline in such a way that the
ball moves parallel to the slope of the incline while going through the centre
of the hoop.
Height = 4m
To find:
calculate the time taken by the ball to reach the hoop in second
Solution:
cos thetha = 4/5
Hence
Theta = 37°
Maximum height = 4m (given)
H max = u²sin²alpha/ 2g cos theta
= 4
u²sin²alpha = 8g cos theta
u sin alpha = √80cos theta
u sin alpha = 8
Now we have to calculate time
T = 2 u sin alpha/2 g cos 37
= 2*8/2*10*(4/5)
= 16/16
= 1 second.
Hence,
The time taken by the ball to reach the hoop is one second.
Answer:
the answer is 1sec only