Question

A man is twice as his son. 20 years ago, the age of man was 12 times the age of his son. Find their present age.

Answer 1

Answer:

Step-by-step explanation:

let the man be x and the son be y.

(x - 20) = 12(y - 20)

we know that x = 2y

substituting x in the equation we get,

2y - 20 = 12y - 240

220 = 10y

y = 22 years

∴ age of son is 22 years and age of man is 44 years