Question

A man is twice as old as his son 20 year ago the age of the man was twelve time the age of the son find the present ages​

Answer 1

son age be x

man age be 2x

20 year ago son age = x- 20

20 year ago man age = 2x - 20

12 ( x-20) = 2x - 20

12x - 240 = 2x - 20

12x - 2x = - 20 + 240

10 x = 220

x = 220 / 10

x = 22

son age = 22 years

man age = 2 × 22 = 44 years

hope this helps you
please Mark's as brainlist

Answer 2

men age = 2x - 20

son = x

=12x = 2x-20

= 10x = -20

x = -20/-10

x= 2

son age 2year and fater age is 24 year