Question

A man is twice as old as his son. 20 years ago, the age of the man was 12 times the age of the son.
Find their present ages.

Answer 1

Answer:

Step-by-step explanation:

Given :-

A man is twice as old as his son.

20 years ago, the age of the man was 12 times the age of the son.

To Find :-

The Present Age

Solution :-

Let son's present age be x years

And the father's present age be 2x years

20 years ago

Son's age be x - 20 years

And father's age be 2x - 20 years

According to the Questions

⇒ 12 (x - 20) = 2x - 20

⇒ 12x - 240 = 2x - 20

⇒ 12x - 2x = 240 - 20

⇒ 10x = 220

⇒ x = 220/10

⇒ x = 22

Present age of son = x = 22 years

Present age of father = 2x = 2 × 22 = 44 years

Answer 2

Answer:

Son's age is 22 years

Father's age is 44 years

Step-by-step explanation:

Let the age of son be x

So, the age of Fathers will be 2x

Before 20 years there age will be,

Son's age be=x-20

Father's age be=2x-20

So,

2x-20=12(x-20)

2x-20=12x-240

10x=220

x=22

Hence Son's age is 22 years

Father's age is 44 years