Question

A man is twice as old as his son. 20 years ago, the age of the man was 12 times the age of the son. Find their present ages.

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Answer 1

Answer:

Son's present age = x = 22 years

Father's present age = 2x = 2 × 22 = 44 years

Step-by-step explanation:

Let the son's age be x and the father's age be 2x

Before 20 years :

Son's age = x - 20

Father's age = 12 ( x - 20 ) = 12x - 240 = 2x - 20

12x - 240 = 2x - 20

12x - 2x = 240 - 20

10x = 220

x = 220/10

=> x = 22

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Answer 2

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