Question

A man is twice as old as his son.Five years ago, four times as old as his son.Find their present ages ​

Answer 1

Answer:

Step-by-step explanation:

let the son age be x

then the man age will be 2x

five years ago son age was = (x-5)

so the son age = 4 (x-5)

4 (x-5) = (x-5)

4x-20 = x-5

4x-x = -5+20

3x = 15

x = 15/3

x = 5

father age = 2x = 5×2 = 10 years

son age = x = 5years