Question

A Man is twice as Old as his son. five years ago,the ratio of their ages was 9:4. find the sons present age​

Answer 1

Answer:

10 and 40 years

Step-by-step explanation:

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son =x+5

Present age of father =7x+5

5 years later their age will (x+10) and (7x+10)

∴7x+10=3(x+10)

7x−3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years

and the present age of father=7x+5=35+5=40years

Answer 2

Answer:

Present age of son is 25 years

Step-by-step explanation:

Let the present age of son = x years

Let the present age of man = y years

By the first given condition ,

a man is twice as old as his son

y = 2x

2x - y = 0 ------------(i)

Five years ago,

sons age = x-5 years and

man's age = y-5 years

By the second given condition ,

y-5 9

_____. = ____

x-5 4

4(y-5) = 9(x-5)

9x-4y=25 ----------(ii)

Solving eq. (i) & (ii)

x= 25

y=50

Therefore , the son's present age =25 years .