Question

A man is twice as old as his son.Ten years ago,the man was thrice as old as his son. find theri present ages.

Answer 1

Let the man's age be x and his son's age be y.
Then, x = 2y
x-2y=0 ………(1)
Also, x-10 = 3*(y-10)
x-3y=-30+10
x-3y=-20 ………………(2)
On doing (1) - (2) We get,
y = 20.
So, x = 2y
x = 2*20
x = 30.
Therefore, the father's age is 40 and the son's age is 20.
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Answer 2

Hi bro,

Continuing from pic :
x-2y=0
=>x-40=0
=>x=40= Man

Hope you find my answer useful and hope you mark my answer as brainliest !