Question

A man is twice older as his son 20 years ago the age of the man was 12 times the age of the son.find their present age?

Answer 1

Hi friend,

Let son be x years
father = 2x
..
20 years ago
son = x-20
father = 2x-20
..
2x-20=12*(x-20)
2x-20 = 12x -240
add 20 to both sides


2x = 12x-240+20
2x=12x-220
add -12x to both sides
2x-12x= 12x-12x-220
-12x+2x= -240+20
-10x= -220
divide by -10
x= -220/-10
x=22 son's age
Father's age = 2*22 = 44 years

Hope this helps you....
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