Question

A man is walking at a speed of 9km h. After every 1 kilometre he takes rest for 9 minutes. How much time will he take to cover a distance of 27 km.a) 6 hr b) 6 hr. 45 min c) 6 hr. 54 min d) 6 hrs. 35 min​

Answer 1

Given :-

• Speed of a man, v = 9 km/h
• After every km he takes rest for 9 minutes.

To Find :-

• The time taken by him to cover a distance of 27 km.

Solution :-

If he did not stops, time taken by him is :

☛  $\sf{t = \dfrac{27\:km}{9\:km/hr} }=3\: hr=180\: min}$

The number of stops in his journey is given by :

☛  $\sf{n = \dfrac{27}{1} }-1=26}$

He takes a rest for 9 min. So, total delay in 26 stops = (26 × 9) minutes = 234 minutes.

Total time to cover the distance is :

➩  T = 180 min + 234 min

➩  T = 414 min

➩  T = 6.9 hours

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Answer 2

Answer:a

Step-by-step explanation: